LeetCode 1242. Web Crawler Multithreaded--Java 解法--网路爬虫并发系列--ConcurrentHashMap/Collections.synchronizedList

2020/02/12 LeetCode 共 4479 字,约 13 分钟

题目地址:Web Crawler Multithreaded - LeetCode

Given a url startUrl and an interface HtmlParser, implement a Multi-threaded web crawler to crawl all links that are under the same hostname as startUrl.

Return all urls obtained by your web crawler in any order.

Your crawler should:

  • Start from the page: startUrl
  • Call HtmlParser.getUrls(url) to get all urls from a webpage of given url.
  • Do not crawl the same link twice.
  • Explore only the links that are under the same hostname as startUrl.

As shown in the example url above, the hostname is example.org. For simplicity sake, you may assume all urls use http protocol without any port specified. For example, the urls http://leetcode.com/problems and http://leetcode.com/contest are under the same hostname, while urls http://example.org/test and http://example.com/abc are not under the same hostname.

The HtmlParser interface is defined as such:

interface HtmlParser {
  // Return a list of all urls from a webpage of given url.
  // This is a blocking call, that means it will do HTTP request and return when this request is finished.
  public List<String> getUrls(String url);

Note that getUrls(String url) simulates performing a HTTP request. You can treat it as a blocking function call which waits for a HTTP request to finish. It is guaranteed that getUrls(String url) will return the urls within 15ms. Single-threaded solutions will exceed the time limit so, can your multi-threaded web crawler do better?

Below are two examples explaining the functionality of the problem, for custom testing purposes you’ll have three variables urls, edges and startUrl. Notice that you will only have access to startUrl in your code, while urls and edges are not directly accessible to you in code.

Follow up:

  • Assume we have 10,000 nodes and 1 billion URLs to crawl. We will deploy the same software onto each node. The software can know about all the nodes. We have to minimize communication between machines and make sure each node does equal amount of work. How would your web crawler design change?
  • What if one node fails or does not work?
  • How do you know when the crawler is done?

Example 1:

urls = [
edges = [[2,0],[2,1],[3,2],[3,1],[0,4]]
startUrl = "http://news.yahoo.com/news/topics/"
Output: [

Example 2:

urls = [
edges = [[0,2],[2,1],[3,2],[3,1],[3,0]]
startUrl = "http://news.google.com"
Output: ["http://news.google.com"]
Explanation: The startUrl links to all other pages that do not share the same hostname.


  • 1 <= urls.length <= 1000
  • 1 <= urls[i].length <= 300
  • startUrl is one of the urls.
  • Hostname label must be from 1 to 63 characters long, including the dots, may contain only the ASCII letters from ‘a’ to ‘z’, digits from ‘0’ to ‘9’ and the hyphen-minus character (’-’).
  • The hostname may not start or end with the hyphen-minus character (’-’).
  • See: https://en.wikipedia.org/wiki/Hostname#Restrictions_on_valid_hostnames
  • You may assume there’re no duplicates in url library.






class Solution {
    private final Set<String> set = Collections.newSetFromMap(new ConcurrentHashMap<String, Boolean>());
    private final List<String> result = Collections.synchronizedList(new ArrayList<String>());
    private String HOSTNAME = null;

    public boolean judgeHostname(String url) {
        int idx = url.indexOf('/', 7);
        String hostName = (idx != -1) ? url.substring(0, idx) : url;
        return hostName.equals(HOSTNAME);

    private void initHostName(String url) {
        int idx = url.indexOf('/', 7);
        HOSTNAME = (idx != -1) ? url.substring(0, idx) : url;

    public void getUrl(String startUrl, HtmlParser htmlParser) {
        List<String> res = htmlParser.getUrls(startUrl);
        List<Thread> threads = new ArrayList<>();
        for (String url : res) {
            if (judgeHostname(url) && !set.contains(url)) {
                threads.add(new Thread(() -> {
                    getUrl(url, htmlParser);
        for (Thread thread : threads) {
        try {
            for (Thread thread : threads) {
        } catch (InterruptedException e) {

    public List<String> crawl(String startUrl, HtmlParser htmlParser) {
        getUrl(startUrl, htmlParser);
        return result;



我尝试使用 Future, CountDownLatch,但效果都不好。最关键的是运行速度没有直接新建线程快!!


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